Question:

A gas undergoes physical adsorption on a surface and follows the given Freundlich adsorption isotherm equation
\(\frac{x}{m} = kp^{0.5}\)
Adsorption of the gas increase with :

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\(\frac{x}{m}\) rises with \(p\) in the Freundlich equation, and physisorption is exothermic so it is favoured by low temperature.
Updated On: Nov 5, 2026
  • Decrease in p and increase in T
  • Increase in p and decrease in T
  • Decrease in p and decrease in T
  • Increase in p and increase in T
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The Correct Option is B

Solution and Explanation

From \(\frac{x}{m} = kp^{0.5}\), the extent of adsorption increases as pressure \(p\) increases (the exponent is positive).
The adsorption is physical (physisorption), which is exothermic (\(\Delta H\) negative, about 20-40 kJ/mol). By Le Chatelier's principle, a decrease in temperature favours the exothermic process, so adsorption increases with decrease in \(T\).
Hence adsorption increases with increase in \(p\) and decrease in \(T\).
Answer: (2) Increase in p and decrease in T
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