To solve this question, we need to understand the principle of adsorption and the methods mentioned in the options.
Adsorption Principle: Adsorption is the process by which atoms, ions, or molecules from a substance (usually a gas, liquid, or dissolved solid) adhere to a surface of the adsorbent. This process is utilized in various purification techniques where substances are selectively retained on the surface of the adsorbent material.
Now, let's evaluate each of the given options:
Conclusion: Among the given options, Chromatography is the method that relies on the principle of adsorption for purification. The stationary phase in chromatography adsorbs different components of the mixture to different extents, allowing separation and purification of the components.
Principle used in chromatography is adsorption.
Thus the correct answer is Option 2: Chromatography.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

| Column I (Chemical reactions) | Column II (Enzymes used) | ||
| (i) | Glucose → CO2 + Ethanol | a | Pepsin |
| (ii) | Sucrose→Glucose + Fructose | b | Diastase |
| (iii) | Starch →Maltose | c | Zymase |
| (iv) | Protein→Amino acids | d | Invertase |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)