Question:

A force of 26 N is acting on a body of mass 2 kg in the x-y plane. The force is directed at an angle \(\cos^{-1}\left(\frac{12}{13}\right)\) with the x-axis. The component of acceleration along y-axis is

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Always find sine using \(\sin\theta = \sqrt{1-\cos^2\theta}\) when cosine is given.
Updated On: Feb 11, 2026
  • \(8 \, \text{m s}^{-2}\)
  • \(3 \, \text{m s}^{-2}\)
  • \(5 \, \text{m s}^{-2}\)
  • \(12 \, \text{m s}^{-2}\)
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The Correct Option is C

Solution and Explanation

Step 1: Resolving the force.
Given \[ \cos\theta = \frac{12}{13} \Rightarrow \sin\theta = \frac{5}{13} \]
Step 2: Calculating y-component of force.
\[ F_y = F \sin\theta = 26 \times \frac{5}{13} = 10 \, \text{N} \]
Step 3: Using Newton’s second law.
\[ a_y = \frac{F_y}{m} = \frac{10}{2} = 5 \, \text{m s}^{-2} \]
Step 4: Conclusion.
The acceleration along y-axis is \(5 \, \text{m s}^{-2}\).
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