Question

A die is thrown once. Find the probability of getting (i) a prime number (ii) an odd number.

Hint:

When calculating probabilities, count the number of favorable outcomes and divide it by the total number of possible outcomes.

Answer 1

A standard die has six faces, numbered from 1 to 6.
(i) Probability of getting a prime number:
Prime numbers between 1 and 6 are 2, 3, and 5. So, there are 3 favorable outcomes. The total number of outcomes (since the die has 6 faces) is 6.
The probability of getting a prime number is given by: \[ P(\text{prime}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{6} = \frac{1}{2} \] (ii) Probability of getting an odd number:
Odd numbers between 1 and 6 are 1, 3, and 5. So, there are 3 favorable outcomes. The total number of outcomes is still 6.
The probability of getting an odd number is: \[ P(\text{odd}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{6} = \frac{1}{2} \]