Question:

A cycle wheel of radius $0.5\, m$ is rotated with constant angular velocity of $10 \,rad/s$ in a region of magnetic field of $0.1\, T$ which is perpendicular to the plane of the wheel. The $EMF$ generated between its centre and the rim is,

Updated On: Jun 9, 2024

0.25 V
0.125 V
0.5 V
zero

Hide Solution

Verified By Collegedunia

The Correct Option is B

Solution and Explanation

The formula to calculate emf is

$E = \frac{B \omega l^2}{2}$

$E$ is the electromotive force (EMF) generated.

$B$ is the magnetic field strength (0.1 Tesla in this case).

$l$ is the length, 0.5m

ω is the angular velocity (10 radians per second).

To calculate the value of EMF, let's put the values in the formula:

$E = \frac{B \omega l^2}{2}$
$=\frac{0.1(10)(0.5)^2}{2} = 0.125\,v$

Was this answer helpful?

Questions Asked in NEET exam

View More Questions

Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

When we place the conductor in a changing magnetic field.
When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

e = induced voltage
N = number of turns in the coil
Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
t = time

Applications of Electromagnetic Induction

Electromagnetic induction in AC generator
Electrical Transformers
Magnetic Flow Meter