Step 1: Formula
Partial pressure $P_i \propto$ number of moles ($n_i$). Since masses ($m$) are equal, $n_i = \frac{m}{M_i}$.
Step 2: Molar Mass Comparison
- $H_2$: 2 g/mol
- $He$: 4 g/mol
- $Ne$: 20 g/mol
- $CO_2$: 44 g/mol
Step 3: Analysis
$P_i \propto \frac{1}{M_i}$. The gas with the **highest** molar mass will have the **lowest** number of moles and thus the **minimum** partial pressure.
Step 4: Conclusion
$CO_2$ has the highest molar mass (44), so it exerts the minimum pressure.
Final Answer:(C)