Question:
A compound of Xe and F is found to have atomic ratio Xe : F as 0.4 : 2.4, Find the oxidation number of Xe ?
A compound of Xe and F is found to have atomic ratio Xe : F as 0.4 : 2.4, Find the oxidation number of Xe ?
Show Hint
Always reduce atomic ratios to the simplest whole number to find the molecular formula first.
Updated On: Apr 26, 2026
- -4
- Zero
- +4
- +6
Show Solution
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The Correct Option is D
Solution and Explanation
Step 1: Simplify Ratio
Ratio $\text{Xe} : \text{F} = 0.4 : 2.4$.
Divide both by 0.4: $\text{Xe} : \text{F} = 1 : 6$.
Step 2: Chemical Formula
The formula of the compound is $\text{XeF}_6$.
Step 3: Oxidation Number
Let oxidation state of $\text{Xe}$ be $x$.
$x + 6(-1) = 0$
$x - 6 = 0 \to x = +6$.
Final Answer: (D)
Ratio $\text{Xe} : \text{F} = 0.4 : 2.4$.
Divide both by 0.4: $\text{Xe} : \text{F} = 1 : 6$.
Step 2: Chemical Formula
The formula of the compound is $\text{XeF}_6$.
Step 3: Oxidation Number
Let oxidation state of $\text{Xe}$ be $x$.
$x + 6(-1) = 0$
$x - 6 = 0 \to x = +6$.
Final Answer: (D)
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