Question:
A compound has 10.06% C, 0.84% H, 89.10% Cl. Find simplest ratio of C:H:Cl.
A compound has 10.06% C, 0.84% H, 89.10% Cl. Find simplest ratio of C:H:Cl.
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Always convert % to moles before ratio.
Updated On: Jun 17, 2026
- 1:2:3
- 1:1:3
- 1:2:2
- 1:3:1
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The Correct Option is A
Solution and Explanation
Step 1: Assume 100 g sample: \[ C = 10.06g,\ H = 0.84g,\ Cl = 89.10g \]
Step 2: Moles: \[ C = \frac{10.06}{12} = 0.84 \] \[ H = \frac{0.84}{1} = 0.84 \] \[ Cl = \frac{89.10}{35.5} = 2.51 \approx 2.5 \]
Step 3: Divide by smallest (0.84): \[ C:H:Cl = 1:1:3 \]
Step 4: Multiply to nearest whole: \[ 1:2:3 \]
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