Question

A cold storage system used to store potatoes is observed to remove 2500 calories of heat every second. What will be the capacity of refrigeration system installed in the cold store in terms of ton of refrigeration ?

• A. 2.5
• B. 3
• C. 1
• D. 4

Hint:

Remember the metric standard:
\[ 1\text{ TR} = 50\text{ kcal/min} \] Multiplying \(2.5\text{ kcal/s}\) by \(60\) yields \(150\text{ kcal/min}\), which immediately simplifies to \(3\text{ TR}\).

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
Refrigeration capacity is commonly measured in Tons of Refrigeration (TR). One TR is defined as the rate of heat transfer required to freeze 1 short ton of water at \(0 ^\circ\text{C}\) into ice at \(0 ^\circ\text{C}\) in 24 hours.

Step 2: Key Formula or Approach:
1. Convert heat removal rate from calories per second to kilocalories per minute (kcal/min).
2. Use the metric conversion definition for TR:
\[ 1 \text{ TR} \approx 50 \text{ kcal/min} = 3000 \text{ kcal/h} \]

Step 3: Detailed Explanation:
Given heat removal rate:
\[ Q = 2500 \text{ cal/s} = 2.5 \text{ kcal/s} \] Convert this rate to per minute:
\[ Q = 2.5 \text{ kcal/s} \times 60 \text{ s/min} = 150 \text{ kcal/min} \] Now, convert the capacity to Tons of Refrigeration (TR):
\[ \text{Capacity in TR} = \frac{150 \text{ kcal/min}}{50 \text{ kcal/min/TR}} = 3 \text{ TR} \]

Step 4: Final Answer:
The correct option is 2, which corresponds to 3.