Question:

A coil of n turns and resistance $R \Omega$ is connected in series with resistance $R/4$. The combination is moved for time t second through magnetic flux $\phi_1$ to $\phi_2$. The induced current in the circuit is

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Induced current depends on the total resistance of the closed loop, including external resistors.
Updated On: Apr 30, 2026
  • $\frac{2n(\phi_1 - \phi_2)}{5Rt}$
  • $\frac{4n(\phi_1 - \phi_2)}{5Rt}$
  • $\frac{3n(\phi_1 - \phi_2)}{4Rt}$
  • $\frac{5n(\phi_1 - \phi_2)}{3Rt}$
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The Correct Option is B

Solution and Explanation

Step 1: Induced EMF
$e = n \frac{d\phi}{dt} = n \frac{(\phi_1 - \phi_2)}{t}$
Step 2: Total Resistance
$R_{total} = R + \frac{R}{4} = \frac{5R}{4}$
Step 3: Induced Current
$I = \frac{e}{R_{total}} = \frac{n(\phi_1 - \phi_2)}{t} \div \frac{5R}{4}$
$I = \frac{4n(\phi_1 - \phi_2)}{5Rt}$
Step 4: Conclusion
The induced current is $\frac{4n(\phi_1 - \phi_2)}{5Rt}$.
Final Answer:(B)
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