Question:
A circular current carrying coil has a radius \( R \). The distance from the center of the coil on the axis, where the magnetic induction will be \( \frac{1}{8} \) to its value at the center of the coil is?
A circular current carrying coil has a radius \( R \). The distance from the center of the coil on the axis, where the magnetic induction will be \( \frac{1}{8} \) to its value at the center of the coil is?
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The magnetic induction on the axis of a coil decreases as the distance from the coil increases.
Updated On: Jan 12, 2026
- \( \frac{R}{\sqrt{3}} \)
- \( \frac{R}{\sqrt{5}} \)
- \( \sqrt{2} R \)
- \( \frac{2 R}{\sqrt{3}} \)
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The Correct Option is B
Solution and Explanation
The magnetic induction at a point on the axis of a circular coil is related to the distance from the center of the coil. Using the formula for the magnetic field on the axis of a coil, the distance is calculated where the induction is \( \frac{1}{8} \) of the value at the center.
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