Question:
A circle of radius \(r\) is drawn in a uniform electric field \(E\) as shown in figure. If \(V_A, V_B, V_C\) and \(V_D\) are the potentials at \(A,B,C\) and \(D\) respectively, then:
center
A circle of radius \(r\) is drawn in a uniform electric field \(E\) as shown in figure. If \(V_A, V_B, V_C\) and \(V_D\) are the potentials at \(A,B,C\) and \(D\) respectively, then:
center
Show Hint
In uniform electric field:
\[
V=-Ex
\]
Potential depends only on displacement along field direction.
Updated On: Jun 17, 2026
- \(V_A=V_B,\;V_C=V_D\)
- \(V_A>V_B,\;V_C=V_D\)
- \(V_A=V_B,\;V_C<V_D\)
- \(V_A>V_B,\;V_C<V_D\)
Show Solution
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The Correct Option is C
Solution and Explanation
In uniform electric field directed horizontally:
\[
V=-Ex
\]
Potential depends only on horizontal coordinate.
Points \(A\) and \(B\) have same \(x\)-coordinate.
Therefore:
\[
V_A=V_B
\]
Point \(D\) lies left of \(C\).
Potential decreases along direction of electric field.
Hence:
\[
V_D>V_C
\]
Thus:
\[
\boxed{V_A=V_B,\;V_C<V_D}
\]
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