Question:
A charged particle moving in a uniform magnetic field loses 4% of its kinetic energy. The radius of curvature of its path changes by
A charged particle moving in a uniform magnetic field loses 4% of its kinetic energy. The radius of curvature of its path changes by
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In magnetic fields:
• Radius ∝ v
• Kinetic energy ∝ v²
Updated On: Mar 20, 2026
- \(2\%\)
- \(4\%\)
- \(10\%\)
- 12%
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The Correct Option is A
Solution and Explanation
Step 1: Radius of circular motion: r = (mv)/(qB)
Step 2: Since K ∝ v², a 4% decrease in kinetic energy gives: (Δ v)/(v) = (1)/(2) × 4% = 2%
Step 3: Radius depends linearly on velocity, hence radius decreases by 2%.
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