Question:

A charged particle is moving parallel to a uniform magnetic field. Then the force on the charged particle is

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Magnetic force is maximum when \[ \theta=90^\circ, \] for which \[ F=qvB. \] If the particle moves parallel or antiparallel to the magnetic field, \[ \theta=0^\circ \text{ or }180^\circ, \] and hence \[ F=0. \]
Updated On: Jul 29, 2026
  • \[ qvB \]
  • \[ \frac{B}{qv} \]
  • \[ \frac{v^2B}{q} \]
  • Zero
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The Correct Option is D

Solution and Explanation

Concept: The magnetic force acting on a charged particle moving in a magnetic field is given by \[ F=qvB\sin\theta, \] where \[ q=\text{charge}, \qquad v=\text{velocity}, \qquad B=\text{magnetic field}, \] and \(\theta\) is the angle between \(\vec v\) and \(\vec B\).

Step 1: Identify the angle between velocity and magnetic field. The particle moves parallel to the magnetic field. Therefore, \[ \theta=0^\circ. \]

Step 2: Substitute into the magnetic force equation. \[ F=qvB\sin0^\circ. \] Since \[ \sin0^\circ=0, \] \[ F=0. \]

Step 3: State the result. No magnetic force acts on a charged particle moving parallel (or antiparallel) to the magnetic field. \[ \boxed{F=0} \] \[ \boxed{\text{Answer = (D)}} \]
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