Question:
A charge +q is at a distance L/2 above a square of side L. Then what is the flux linked with the surface?
A charge +q is at a distance L/2 above a square of side L. Then what is the flux linked with the surface?
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Use symmetry and Gauss’s law to simplify flux problems.
Updated On: Mar 18, 2026
- q4₀
- 2q3₀
- q6₀
- 6q₀
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The Correct Option is C
Solution and Explanation
Step 1: Imagine the square as one face of a cube.
Step 2: Charge lies at center of cube.
Step 3: Flux through one face: Φ=(q)/(6₀)
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