Question:
A Carnot engine operates between temperatures T₁ and T₂ (T₁ > T₂). If T₁ is increased by ∆T and T₂ is decreased by ∆T, its efficiency will:
A Carnot engine operates between temperatures T₁ and T₂ (T₁ > T₂). If T₁ is increased by ∆T and T₂ is decreased by ∆T, its efficiency will:
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Key Exam Tip:
Carnot efficiency increases with a larger temperature difference between the hot reservoir ($T_1$) and the cold reservoir ($T_2$).
Carnot efficiency increases with a larger temperature difference between the hot reservoir ($T_1$) and the cold reservoir ($T_2$).
Updated On: May 29, 2026
- Increase
- Decrease
- Remain constant
- Depend on the working substance
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The Correct Option is A
Solution and Explanation
Carnot efficiency $\eta = 1 - T_2/T_1$.
Increasing $T_1$ and decreasing $T_2$ increases the difference $T_1 - T_2$ and decreases the ratio $T_2/T_1$.
Since $\eta = 1 - (T_2/T_1)$, a decrease in the ratio $T_2/T_1$ leads to an increase in efficiency.
Final Answer: \(\boxed{A}\)
Increasing $T_1$ and decreasing $T_2$ increases the difference $T_1 - T_2$ and decreases the ratio $T_2/T_1$.
Since $\eta = 1 - (T_2/T_1)$, a decrease in the ratio $T_2/T_1$ leads to an increase in efficiency.
Final Answer: \(\boxed{A}\)
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