A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is M. If the radius of the tube is doubled, mass of water that will rise in the capillary tube will now be
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In capillary rise problems:
Mass of liquid risen ∝ radius of tube
Step 1: Height of capillary rise:
h ∝ (1)/(R)
Step 2: Volume of water in tube:
V = π R² h ∝ π R² · (1)/(R) ∝ R
Step 3: Mass of water:
M ∝ V ∝ R
If radius is doubled:
M' = 2M