Step 1: Formula / Definition}
\[
\mathrm{LiAlH_4} \rightarrow \mathrm{H^-} \text{ nucleophile}
\]
Step 2: Calculation / Simplification}
Unsymmetrical epoxide opening follows \(S_N2\) at less hindered carbon.
\(\mathrm{H^-}\) attacks terminal \(\mathrm{CH_2}\) carbon.
Ring opens forming alkoxide on secondary carbon.
Protonation yields \(\mathrm{CH_3CH(OH)CH_3}\) (Propan-2-ol).
Step 3: Final Answer
\[
\mathrm{CH_3CH(OH)CH_3}
\]