Question:

A body of mass 1kg begins to move under the action of a time dependent force \(\overset{⃗}{F} = (t\hat{i}+3t^2\hat{j}) \text{N}\) where \(\hat{i}\) and \(\hat{j}\) are the unit vectors along x and y axis. The power developed by the above force at time \(t = 2 \text{s}\) will be (in watt)

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Find velocity by integrating acceleration, then use P = F dot v.
Updated On: Oct 1, 2026
  • \(100\)
  • \(50\)
  • \(25\)
  • \(5\)
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The Correct Option is A

Solution and Explanation

Step 1: Acceleration
With \(m = 1\ \text{kg}\), \(\vec a = \vec F = t\hat i + 3t^2\hat j\).

Step 2: Velocity
Starting from rest, \(\vec v = \frac{t^2}{2}\hat i + t^3\hat j\). At \(t=2\): \(\vec v = 2\hat i + 8\hat j\).

Step 3: Force at t = 2
\(\vec F = 2\hat i + 12\hat j\).

Step 4: Power
\[ P = \vec F\cdot\vec v = 2\times2 + 12\times8 = 4 + 96 = 100\ \text{W} \]
Option (A).

Final Answer:
The power is 100 W. \[ \boxed{\text{(A)}\ 100\ \text{W}} \]
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