Question:

A body of mass 0.7 kg executes simple harmonic motion of amplitude 7 cm and period 0.2 s. The magnitude of the maximum force on it is:

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In SHM, maximum force always occurs at extreme position: \(F_{max} = m\omega^2 A\).
Updated On: Jun 19, 2026
  • 48.3 N
  • 60.6 N
  • 24.8 N
  • 52.2 N
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The Correct Option is A

Solution and Explanation

Step 1: Formula for maximum force in SHM.
\[ F_{max} = m\omega^2 A \]

Step 2: Given values.

\[ m = 0.7\,kg,\quad A = 7\,cm = 0.07\,m,\quad T = 0.2\,s \]

Step 3: Find angular frequency.

\[ \omega = \frac{2\pi}{T} = \frac{2\pi}{0.2} = 10\pi \]

Step 4: Compute \(\omega^2\).

\[ \omega^2 = 100\pi^2 \approx 986.96 \]

Step 5: Substitute values.

\[ F_{max} = 0.7 \times 986.96 \times 0.07 \]

Step 6: Final calculation.

\[ F_{max} \approx 48.3\,N \]
Final Answer: \[ \boxed{48.3\,N} \]
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