Question:

A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time?

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With upward as positive, \(v=u-gt\): a single straight line of constant negative slope that crosses zero at the top and continues into negative values.
Updated On: Nov 11, 2026
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The Correct Option is D

Solution and Explanation

Taking upward as positive, \(v=u-gt\). The velocity starts at \(+u\), decreases uniformly to zero at the highest point (\(t=\frac{u}{g}\)), and continues decreasing uniformly to negative values while the body falls. The slope \(-g\) is constant throughout, so the graph is one straight line with negative slope passing through the time axis.
Graph (1) shows a bounce (the slope changes sign), graph (2) shows velocity first rising from zero, graph (3) has different slopes for the upward and downward parts (the acceleration would change), graph (4) is a single straight line crossing the axis.
Answer: (4) the straight line with constant negative slope crossing the time axis
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