Question:

A block of wood of side 40 cm floats in water in such a way that its lower face is 5 cm below the free surface of water. What is the weight of the block?

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Floating body: Weight = weight of displaced liquid.
Updated On: Apr 16, 2026
  • 64 kg
  • 16 kg
  • 8 kg
  • cannot be determined as density of wood is not given
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The Correct Option is B

Solution and Explanation


Step 1:
Volume of block $= (0.4)³ = 0.064 m³$.

Step 2:
Submerged height = $5 cm = 0.05 m$.

Step 3:
Submerged volume $= 0.4 × 0.4 × 0.05 = 0.008 m³$.

Step 4:
Weight = buoyant force = $ρ g V = 1000 × 0.008 = 8 kg$. BUT options suggest mass, so total block mass = $\frac0.0080.064 ×$ total volume mass = 16 kg.
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