A block of mass \( m \) is moving with velocity \( v \) on a smooth horizontal surface. If a constant force \( F \) is applied to the block, what is the work done by this force after 5 seconds?
Show Hint
- \( Fv \)
- \( F \cdot 5v \)
- \( \frac{1}{2} mv^2 \)
- \( F \cdot 5 \)
The Correct Option is A
Solution and Explanation
The work done by a constant force \( F \) is given by the formula: \[ W = F \cdot d, \] where \( d \) is the displacement of the block. If the block is moving with velocity \( v \), after time \( t = 5 \) seconds, the displacement will be \( d = v \cdot 5 \).
Thus, the work done is: \[ W = F \cdot (5v) = Fv. \]
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