We are given:
- Mass of the block \(m = 2\, \text{kg}\)
- Force applied \(F = 10\, \text{N}\)
- The surface is smooth, i.e., there is no friction.
Step 1: Use Newton’s Second Law of Motion
According to Newton’s Second Law,
\[
F = m \cdot a
\]
Solving for acceleration \(a\):
\[
a = \frac{F}{m}
\]
\[
a = \frac{10}{2} = 5 \, \text{m/s}^2
\]
Step 2: Final Answer
Thus, the acceleration of the block is \(5 \, \text{m/s}^2\).
Answer: The correct answer is option (2) \(5 \, \text{m/s}^2\).