Question:

A binary solid has a primitive cubical structure with B$^-$ ions constituting the lattice points and A$^+$ ions occupying 25% of its tetrahedral holes. The molecular formula of the crystal is

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Tetrahedral voids = 2 × number of atoms in unit cell.
Updated On: May 8, 2026
  • A$_2$B
  • AB$_3$
  • AB$_2$
  • A$_2$B$_3$
  • A$_2$B$_5$
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The Correct Option is C

Solution and Explanation

Concept:
• Primitive cubic lattice has 1 atom per unit cell.
• Number of tetrahedral voids = 2 × number of lattice points.

Step 1:
Count B$^-$ ions.
Primitive cubic → 1 lattice point → 1 B$^-$ ion.

Step 2:
Count tetrahedral voids. \[ \text{Void} = 2 \times 1 = 2 \]

Step 3:
A$^+$ ions occupying 25%. \[ 25% \text{ of 2} = \frac{1}{2} \]

Step 4:
Ratio of A to B. \[ A : B = \frac{1}{2} : 1 = 1 : 2 \]

Step 5:
Final formula. \[ \boxed{AB_2} \]
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