Question:

A battery with a \(12\,\text{V}\) emf has an initial charge of \(80\,\text{A h}\). If the potential across the terminals stays constant until battery is completely discharged, then this battery can deliver energy at the rate of \(120\,\text{W}\) for a time:

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Battery capacity in ampere-hour is given by: \[ \text{Capacity}=I\times t. \] First calculate current using \[ P=VI, \] then determine the operating time.
Updated On: Jun 24, 2026
  • \(16\,\text{h}\)
  • \(8\,\text{h}\)
  • \(4\,\text{h}\)
  • \(5\,\text{h}\)
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The Correct Option is B

Solution and Explanation

Step 1: Write the given battery capacity.
Battery capacity: \[ 80\,\text{A h} \] Voltage: \[ V=12\,\text{V} \] Power supplied: \[ P=120\,\text{W} \]

Step 2: Find the current supplied by the battery.
Using \[ P=VI \] \[ 120=12\times I \] \[ I=10\,\text{A} \]

Step 3: Use battery capacity relation.
Battery capacity is \[ \text{Capacity}=I\times t \] Thus, \[ 80=10\times t \] \[ t=8\,\text{h} \]

Step 4: Final conclusion.
Hence, the battery can supply power for \[ \boxed{8\,\text{h}} \]
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