Question:
A bag contains \(3\) white, \(2\) blue and \(5\) red balls. One ball is drawn at random from this bag. Then, the probability that the ball drawn is not red is
A bag contains \(3\) white, \(2\) blue and \(5\) red balls. One ball is drawn at random from this bag. Then, the probability that the ball drawn is not red is
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For simple probability problems, first count the favorable outcomes and total outcomes, then use
\[
P(E)=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}.
\]
Updated On: Jun 26, 2026
- \(\frac{3}{10}\)
- \(\frac{1}{5}\)
- \(\frac{1}{2}\)
- \(\frac{4}{5}\)
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The Correct Option is C
Solution and Explanation
Step 1: Find the total number of balls.
The bag contains \[ 3 \text{ white balls}, \] \[ 2 \text{ blue balls}, \] and \[ 5 \text{ red balls}. \] Therefore, the total number of balls is \[ 3+2+5=10. \]
Step 2: Find the number of non-red balls.
The non-red balls are the white and blue balls. Thus, \[ 3+2=5. \] Hence, the number of favorable outcomes is \[ 5. \]
Step 3: Apply the probability formula.
We know that \[ P(E)=\frac{\text{Number of favorable outcomes}} {\text{Total number of outcomes}}. \] Therefore, \[ P(\text{not red}) = \frac{5}{10}. \] \[ P(\text{not red}) = \frac{1}{2}. \]
Step 4: Final conclusion.
Hence, \[ \boxed{\frac{1}{2}} \] and the correct option is \[ \boxed{(3)}. \]
The bag contains \[ 3 \text{ white balls}, \] \[ 2 \text{ blue balls}, \] and \[ 5 \text{ red balls}. \] Therefore, the total number of balls is \[ 3+2+5=10. \]
Step 2: Find the number of non-red balls.
The non-red balls are the white and blue balls. Thus, \[ 3+2=5. \] Hence, the number of favorable outcomes is \[ 5. \]
Step 3: Apply the probability formula.
We know that \[ P(E)=\frac{\text{Number of favorable outcomes}} {\text{Total number of outcomes}}. \] Therefore, \[ P(\text{not red}) = \frac{5}{10}. \] \[ P(\text{not red}) = \frac{1}{2}. \]
Step 4: Final conclusion.
Hence, \[ \boxed{\frac{1}{2}} \] and the correct option is \[ \boxed{(3)}. \]
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