Question:

A bag contains 3 black and 2 white balls. A ball is drawn at random and is put back in the bag along with one ball of the same colour. A ball is again drawn at random. What is the probability that it is white?

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Split problems into cases when outcomes affect future probabilities.
Updated On: Apr 30, 2026
  • \(1/5\)
  • \(2/5\)
  • \(1/6\)
  • \(1/12\)
  • \(2/13\)
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The Correct Option is B

Solution and Explanation

Concept: Use total probability considering both first-draw cases.

Step 1:
Initial probabilities. \[ P(W_1)=\frac{2}{5}, P(B_1)=\frac{3}{5} \]

Step 2:
Case 1: First draw is white. New balls: \[ 3B, 3W \] \[ P(W_2|W_1)=\frac{3}{6}=\frac{1}{2} \]

Step 3:
Case 2: First draw is black. New balls: \[ 4B, 2W \] \[ P(W_2|B_1)=\frac{2}{6}=\frac{1}{3} \]

Step 4:
Apply total probability. \[ P(W_2)=P(W_1)P(W_2|W_1)+P(B_1)P(W_2|B_1) \] \[ =\frac{2}{5}\cdot\frac{1}{2}+\frac{3}{5}\cdot\frac{1}{3} \] \[ =\frac{1}{5}+\frac{1}{5}=\frac{2}{5} \]
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