Question:
A and B are two wires whose fundamental frequencies are 256 Hz and 382 Hz respectively. When third harmonic of A and the second harmonic of B are sounded together, the number of beats heard in two second will be
A and B are two wires whose fundamental frequencies are 256 Hz and 382 Hz respectively. When third harmonic of A and the second harmonic of B are sounded together, the number of beats heard in two second will be
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Find the two frequencies, subtract to get beats per second, then multiply by 2 s.
Updated On: Oct 1, 2026
- \(8\)
- \(6\)
- \(4\)
- \(2\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
The \(n\)th harmonic of a stretched wire has frequency \(n\) times the fundamental.
Step 2: Key Formula or Approach
Third harmonic of A: \(3\times256=768\) Hz. Second harmonic of B: \(2\times382=764\) Hz.
Step 3: Detailed Explanation
Beat frequency \(=768-764=4\) Hz, so 4 beats per second.
In two seconds the number of beats is \(4\times2=8\).
Final Answer:
There are 8 beats in two seconds, option (A). \[ \boxed{8\ \text{(A)}} \]
The \(n\)th harmonic of a stretched wire has frequency \(n\) times the fundamental.
Step 2: Key Formula or Approach
Third harmonic of A: \(3\times256=768\) Hz. Second harmonic of B: \(2\times382=764\) Hz.
Step 3: Detailed Explanation
Beat frequency \(=768-764=4\) Hz, so 4 beats per second.
In two seconds the number of beats is \(4\times2=8\).
Final Answer:
There are 8 beats in two seconds, option (A). \[ \boxed{8\ \text{(A)}} \]
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