Question

6.022 × 10\(^23\) molecules of glucose are present in 100 mL of its aqueous solution, what is the concentration of this solution?

• A. 1.0 M
• B. 0.1 M
• C. 0.001 M
• D. 0.01 M

Hint:

To calculate molarity, divide the number of moles by the volume of the solution in liters.

Answer 1

The Correct Option is B

Step 1: Understanding the relation.
The concentration (molarity) of a solution is given by the formula: \[ \text{Molarity} = \frac{\text{Number of moles}}{\text{Volume in Liters}} \] First, calculate the number of moles of glucose using Avogadro's number: \[ \text{Number of moles} = \frac{6.022 \times 10^{23}}{6.022 \times 10^{23}} = 1 \, \text{mol} \] Now, convert the volume of the solution into liters: \[ \text{Volume in Liters} = \frac{100}{1000} = 0.1 \, \text{L} \] Step 2: Calculating the molarity.
\[ \text{Molarity} = \frac{1 \, \text{mol}}{0.1 \, \text{L}} = 0.1 \, \text{M} \] Step 3: Conclusion.
The correct answer is (B) 0.1 M, the molarity of the solution.