Question:

3 moles of an ideal gas at temperature 27C are mixed with 2 moles of an ideal gas at temperature 227C. Determine the equilibrium temperature of the mixture, assuming no loss of energy.

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For ideal gases, equilibrium temperature depends on mole-weighted average.
Updated On: Mar 18, 2026
  • 327C
  • 107C
  • 318C
  • 410C
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The Correct Option is B

Solution and Explanation


Step 1:
Convert temperatures to Kelvin: T₁=300K, T₂=500K
Step 2:
T=(n₁T₁+n₂T₂)/(n₁+n₂) =(3×300+2×500)/(5)=380K
Step 3:
T=380-273=107C
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