Question:
$3.0,g$ of a salt of molecular weight $30$ is dissolved in $250,mL$ of water. The molarity of the solution is
$3.0,g$ of a salt of molecular weight $30$ is dissolved in $250,mL$ of water. The molarity of the solution is
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Chemistry Tip: Always convert mL into litre before using molarity formula.
Updated On: Apr 27, 2026
- $0.1,M$
- $0.2,M$
- $0.3,M$
- $0.4,M$
- $0.5,M$
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The Correct Option is D
Solution and Explanation
Concept:
Molarity is: $$M=\frac{\text{moles of solute}}{\text{volume of solution in litre}}$$
Step 1: Find moles of salt.
Given mass: $$m=3.0g$$ Molecular weight: $$=30g/mol$$ So moles: $$n=\frac{3.0}{30}=0.1\text{ mol}$$
Step 2: Convert volume into litre.
$$250mL=0.250L$$
Step 3: Calculate molarity.
$$M=\frac{0.1}{0.250}=0.4M$$
Hence correct option is (D). :contentReference[oaicite:1]{index=1}
Molarity is: $$M=\frac{\text{moles of solute}}{\text{volume of solution in litre}}$$
Step 1: Find moles of salt.
Given mass: $$m=3.0g$$ Molecular weight: $$=30g/mol$$ So moles: $$n=\frac{3.0}{30}=0.1\text{ mol}$$
Step 2: Convert volume into litre.
$$250mL=0.250L$$
Step 3: Calculate molarity.
$$M=\frac{0.1}{0.250}=0.4M$$
Hence correct option is (D). :contentReference[oaicite:1]{index=1}
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