Step 1: Concept
Sum of all coefficients: $\sum_{r=0}^{21} {}^{21}C_r = 2^{21}$.
Also, ${}^{21}C_r = {}^{21}C_{21-r}$.
Step 2: Analysis
$2^{21} = ({}^{21}C_0 + \dots + {}^{21}C_{10}) + ({}^{21}C_{11} + \dots + {}^{21}C_{21})$.
Since the two halves are equal: $2 \times ({}^{21}C_0 + \dots + {}^{21}C_{10}) = 2^{21}$.
${}^{21}C_0 + {}^{21}C_1 + \dots + {}^{21}C_{10} = 2^{20}$.
Step 3: Calculation
The required sum is $({}^{21}C_0 + {}^{21}C_1 + \dots + {}^{21}C_{10}) - {}^{21}C_0$.
Sum $= 2^{20} - 1$.
Final Answer: (E)