20 meters of wire is available to fence of a flowerbed in the form of a circular sector. If the flowerbed is to have maximum surface area, then the radius of the circle is
Sector of a circle = 2l+r
2r+l = 20
l = 20 -2r
Area = \(\frac {1}{2}\)lr
Area = \(\frac {1}{2}\)*(20-2r)*r = 10r - r2
Now
dA/dx = 10 - 2r
10 - 2r = 0
r = 5 m
If the line ax+by+c=0 is a normal to the curve xy=1, then
The area spherical balloon of radius 6 cm increases at the rate of 2 then find the rate of increase in the volume.
The radius of a cylinder is increasing at the rate 2 cm/sec and its height is decreasing at the rate 3 cm/sec, then find the rate of change of volume when the radius is 3cm and the height is 5 cm.
If y = 4x – 5 is tangent to the curve y2 =px3 +q at (2, 3), then
The extrema of a function are very well known as Maxima and minima. Maxima is the maximum and minima is the minimum value of a function within the given set of ranges.

There are two types of maxima and minima that exist in a function, such as: