Question:
\(2.76\mathrm{g}\) of silver carbonate on being strongly heated yields a residue weighing
\(2.76\mathrm{g}\) of silver carbonate on being strongly heated yields a residue weighing
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The residue is silver metal. CO\(_2\) and O\(_2\) gases escape.
Updated On: Apr 20, 2026
- \(2.16\mathrm{g}\)
- \(2.48\mathrm{g}\)
- \(2.64\mathrm{g}\)
- \(2.32\mathrm{g}\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Silver carbonate decomposes on heating to silver, CO\(_2\), and O\(_2\).
Step 2: Detailed Explanation:
\(2\mathrm{Ag}_2\mathrm{CO}_3 \xrightarrow{\Delta} 4\mathrm{Ag} + 2\mathrm{CO}_2 + \mathrm{O}_2\)
Molar mass of Ag\(_2\)CO\(_3\) = \(2 \times 108 + 12 + 48 = 276\) g/mol.
2 mol (552 g) Ag\(_2\)CO\(_3\) gives 4 mol (432 g) Ag.
So, \(2.76\) g Ag\(_2\)CO\(_3\) gives Ag = \(\frac{432}{552} \times 2.76 = 0.7826 \times 2.76 = 2.16\) g.
Step 3: Final Answer:
2.16 g
Silver carbonate decomposes on heating to silver, CO\(_2\), and O\(_2\).
Step 2: Detailed Explanation:
\(2\mathrm{Ag}_2\mathrm{CO}_3 \xrightarrow{\Delta} 4\mathrm{Ag} + 2\mathrm{CO}_2 + \mathrm{O}_2\)
Molar mass of Ag\(_2\)CO\(_3\) = \(2 \times 108 + 12 + 48 = 276\) g/mol.
2 mol (552 g) Ag\(_2\)CO\(_3\) gives 4 mol (432 g) Ag.
So, \(2.76\) g Ag\(_2\)CO\(_3\) gives Ag = \(\frac{432}{552} \times 2.76 = 0.7826 \times 2.76 = 2.16\) g.
Step 3: Final Answer:
2.16 g
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