10 mL of 1 mM surfactant solution forms a monolayer covering 0.24 cm\(^2\) on a polar substrate. If the polar head is approximated as cube, what is its edge length?
Show Hint
- 1.0 pm
- 2.0 nm
- 0.1 nm
- 2.0 pm
The Correct Option is D
Solution and Explanation
Number of molecules = 10\(^{-5}\) x 6.022 x 10\(^{23}\) = 6.022 x 10\(^{18}\).
Area = 0.24 cm\(^2\) = 0.24 x 10\(^{-4}\) m\(^2\) = 2.4 x 10\(^{-5}\) m\(^2\).
Area per head (a\(^2\)) = 2.4 x 10\(^{-5}\) / 6.022 x 10\(^{18}\) = 3.99 x 10\(^{-24}\) m\(^2\).
Edge a = \(\sqrt{3.99 \times 10^{-24}}\) m = 2.0 x 10\(^{-12}\) m = 2.0 pm.
Answer: (4) 2.0 pm
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