Step 1: Understanding the Concept:
Faraday's first law of electrolysis: \(m = Z \times Q\), where \(m\) is mass deposited, \(Z\) is electrochemical equivalent, and \(Q\) is charge.
Step 2: Detailed Explanation:
Given \(Q = 1\) C. Using \(m = Z \times Q\), we get \(m = Z \times 1 = Z\). So, the mass deposited (m) is equal to the electrochemical equivalent (Z).
Step 3: Final Answer:
1 C electricity deposits the electrochemical equivalent of Ag, which corresponds to option (B).