Let the plane\(P : \stackrel{→}{r} . \stackrel{→}{a} = d\)contain the line of intersection of two planes\(\stackrel{→}{r} . ( \hat{i} + 3\hat{j} - \hat{k} ) = 6\)and\(\stackrel{→}{r} . ( -6\hat{i} + 5\hat{j} - \hat{k} ) = 7\). If the plane P passes through the point (2, 3, 1/2), then the value of \(\frac{| 13a→|² }{d²}\) is equal to
LetA=\(\begin{bmatrix} 2 & -1 \\ 0 & 2 \end{bmatrix}\)If B = I – 5C1(adjA) + 5C2(adjA)2 – …. – 5C5(adjA)5, then the sum of all elements of the matrix B is
The sum of the infinite series\(1 + \frac{5}{6} + \frac{12}{6^2} + \frac{22}{6^3} + \frac{35}{6^4} +\frac{51}{6^5} + \frac{70}{6^6}+…..\)is equal to
Let f : R → R be a function defined by:\(ƒ(x) = (x-3)^{n_1} (x-5)^{n_2} , n_1, n_2 ∈ N\)Then, which of the following is NOT true?
Let f be a real valued continuous function on [0, 1] and\(f(x) = x + \int_{0}^{1} (x - t) f(t) \,dt\)Then, which of the following points (x, y) lies on the curve y = f(x)?
If\(\int_{0}^{2} (\sqrt{2x} - \sqrt{2x - x^2}) \,dx = \int_{0}^{1} \left(1 - \sqrt{1 - y^2} - \frac{y^2}{2}\right) \,dy + \int_{1}^{2} (2 - \frac{y^2}{2}) \,dy + I\)then I equal is
Let a triangle ABC be inscribed in the circle\(x² - \sqrt2(x+y)+y² = 0\)such that ∠BAC= π/2. If the length of side AB is √2, then the area of the ΔABC is equal to :