\(|∫_1^3y^ady|=\frac {364}{3}\)
\(|\frac {1}{a+1}(y^{a+1})|_1^3=\frac {364}{3}\)
\(\frac {3a+1−1}{a+1}=±\frac {364}{3}\)
Solving with (+) sign,
\(\frac {3a+1−1}{a+1}=\frac {364}{3}\)
\(a=5\)
Solving with (-) sign,
\(\frac {3a+1−1}{a+1}=-\frac {364}{3}\)
No a exist
\(∴a=5\)
So, the correct option is (B): \(5\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Read More: Area under the curve formula