Benzene nitrile on reaction with reagent (A) gave product (X). In another reaction with reagent (B) gave product (Y). \(X\) and \(Y\) both form oxime but only \(Y\) gets oxidized with ammoniacal silver nitrate solution. The correct reagents \(A\) and \(B\) respectively are
\[
\begin{aligned}
\text{I. }&\mathrm{CH_3CH_2MgBr,\ H_2O}
\qquad;\qquad
\mathrm{DIBAL\!-\!H,\ H_2O}
\text{II. }&(\mathrm{CH_3CH_2})_2\mathrm{Cd}
\qquad;\qquad
\mathrm{SnCl_2+HCl,\ H_2O}
\text{III. }&\mathrm{CH_3CH_2MgBr,\ H_2O}
\qquad;\qquad
\mathrm{SnCl_2+HCl,\ H_2O}
\text{IV. }&(\mathrm{CH_3CH_2})_2\mathrm{Cd}
\qquad;\qquad
\mathrm{DIBAL\!-\!H,\ H_2O}
\end{aligned}
\]
The correct answer is