A disc is rolling without slipping on a surface. The radius of the disc is \( R \). At \( t = 0 \), the topmost point on the disc is \( A \) as shown in the figure. When the disc completes half of its rotation, the displacement of point \( A \) from its initial position is:
x=logp and y=1/p differential equation
Solution of \( 2^x + 2^{|x|} \geq 2\sqrt{2} \) is: