For the reaction \(N_2(g) + 3H_2(g) \rightleftharpoons 2\text{NH}_3(g)\) at 298 K, the enthalpy change \( \Delta H = -92.4 \, \text{kJ/mol} \). What happens to the equilibrium when temperature is increased?
The enthalpy change for the reaction \(2H_2(g) + O_2(g) → 2H_2O(l)\)is -572 kJ/mol. What is the enthalpy change for the formation of 1 mole of \(H_2O(l)\)}?