Question:
Zinc and cold dil. $ HNO_3$ reacts to produce
Zinc and cold dil. $ HNO_3$ reacts to produce
Updated On: Jun 20, 2022
- NO
- $ N{{O}_{2}} $
- $ N{{H}_{4}}N{{O}_{3}} $
- $ ZnN{{O}_{3}} $
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The Correct Option is C
Solution and Explanation
$CH _{3} OH$ and $C _{2} H _{5} OH$ can be differentiated by using $Na _{2} CO _{3}$ and $I_{2}, C_{2} H_{5} O H$ gives yellow precipitate of $C H I_{3}$ whereas $C H_{3} O H$ does not react with it.
$C _{2} H _{5} OH +4 I _{2}+ Na _{2} CO _{3} \rightarrow \underset{\overset{\text{lodoform}}{\text{(yellow ppt.)}}}{CHI_3}+5 NaI + HCOONa +3 CO _{2}+ H _{2} O$
$C _{2} H _{5} OH +4 I _{2}+ Na _{2} CO _{3} \rightarrow \underset{\overset{\text{lodoform}}{\text{(yellow ppt.)}}}{CHI_3}+5 NaI + HCOONa +3 CO _{2}+ H _{2} O$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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