Concept:
The Greatest Common Divisor (GCD) of two numbers is the largest positive integer that divides both numbers exactly. A prime number is a natural number greater than 1 that has exactly two positive divisors: 1 and itself.
The prime factorization of 150 is:
\[
150 = 2 \times 3 \times 5^2
\]
To determine whether the GCD of 150 and \(x\) is prime, we must know enough information about \(x\) so that the answer is definitely "Yes" or definitely "No".
Step 1: Examine Statement (I) alone.
Statement (I) says:
\[
x \text{ is a prime number}
\]
Since \(x\) can be any prime number, several possibilities arise:
\[
x=2
\]
Then,
\[
\gcd(150,2)=2
\]
and 2 is a prime number.
However, if
\[
x=7
\]
then
\[
\gcd(150,7)=1
\]
and 1 is not a prime number.
Thus, Statement (I) can produce both a prime GCD and a non-prime GCD.
Therefore, Statement (I) alone is not sufficient.
Step 2: Examine Statement (II) alone.
Statement (II) says:
\[
x<4
\]
Since \(x\) is a positive integer,
\[
x\in\{1,2,3\}
\]
Check each case:
For \(x=1\),
\[
\gcd(150,1)=1
\]
which is not prime.
For \(x=2\),
\[
\gcd(150,2)=2
\]
which is prime.
For \(x=3\),
\[
\gcd(150,3)=3
\]
which is also prime.
Since different values of \(x\) lead to different answers, Statement (II) alone is not sufficient.
Step 3: Combine Statements (I) and (II).
From Statement (I):
\[
x \text{ is prime}
\]
From Statement (II):
\[
x<4
\]
The only prime numbers less than 4 are:
\[
x\in\{2,3\}
\]
Now evaluate the GCD in both cases.
If
\[
x=2,
\]
then
\[
\gcd(150,2)=2
\]
which is prime.
If
\[
x=3,
\]
then
\[
\gcd(150,3)=3
\]
which is also prime.
Thus, regardless of whether \(x=2\) or \(x=3\), the GCD is always a prime number.
Therefore, the answer to the question is definitely Yes.
Hence, the two statements together are sufficient.
Final Answer:
\[
\boxed{\text{Both statements (I) and (II) are sufficient}}
\]