Question

X and Y in the following reactions, respectively, are

• A. CH₃COOH and NO⁺
• B. CH₃CHO and NO2\(^+_2\)
• C. EtOSO₃H and NO2\(^+_2\)
• D. EtOSO₃H and NO⁺

Answer 1

The Correct Option is C

To determine the compounds X and Y in the given reactions, we need to analyze them based on known chemical reactions involving sulfuric acid (H₂SO₄). 

Reaction 1: EtOH (Ethanol) + 2 H₂SO₄

When ethanol reacts with concentrated sulfuric acid, it forms ethyl hydrogen sulfate (EtOSO₃H) and water. The reaction is:

\[\text{EtOH} + \text{H}_2\text{SO}_4 \rightarrow \text{EtOSO}_3\text{H} + \text{H}_3\text{O}^+ + \text{HSO}_4^-\]

This indicates that compound X is ethyl hydrogen sulfate (EtOSO₃H).

Reaction 2: HNO₃ + 2 H₂SO₄

When nitric acid (HNO₃) reacts with sulfuric acid, it forms the nitronium ion (NO₂⁺) which is used as an electrophile in nitration reactions. The relevant reaction is:

\[\text{HNO}_3 + 2\text{H}_2\text{SO}_4 \rightarrow \text{NO}_2^+ + \text{H}_3\text{O}^+ + 2\text{HSO}_4^-\]

Thus, compound Y is the nitronium ion (NO₂⁺).

Conclusion: Therefore, the correct answer is that X is EtOSO₃H (ethyl hydrogen sulfate) and Y is NO₂⁺ (nitronium ion).