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write ions produced in an aqueous solution of k 4
Question:
Write ions produced in an aqueous solution of \( K_4[Fe(CN)_6] \). What is the oxidation number of \( Fe \) in this compound?
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The oxidation state of the central metal ion is calculated by balancing the charge of the complex ion.
UP Board XII - 2024
UP Board XII
Updated On:
Mar 5, 2025
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Solution and Explanation
- In aqueous solution, \( K_4[Fe(CN)_6] \) dissociates as: \[ K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}. \] - Oxidation number of \( Fe \) in \( [Fe(CN)_6]^{4-} \) is \( +2 \): \[ x + (-1 \times 6) = -4 \quad \Rightarrow \quad x = +2. \]
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