To determine which equation correctly describes the change in molar conductivity with respect to concentration for a weak electrolyte, we need to consider the dissociation equilibrium and conductivity of weak electrolytes.
Molar conductivity (\(\Lambda_m\)) of an electrolyte is given by:
\(\Lambda_m = \frac{\kappa}{C}\)
where \(\kappa\) is the conductivity and \(C\) is the concentration.
The molar conductivity of a weak electrolyte at any concentration differs from its limiting molar conductivity (\(\Lambda_m^\circ\)) at infinite dilution. For weak electrolytes, as the concentration decreases, \(\Lambda_m\) approaches \(\Lambda_m^\circ\).
The relationship between molar conductivity and concentration for weak electrolytes is rather complex, and various models approximate it. A commonly used relationship involves the degree of dissociation, \(\alpha\), linked with the equilibrium constant (\(K_a\)). For a weak electrolyte:
\(\alpha = \frac{\Lambda_m}{\Lambda_m^\circ}\)
The equilibrium constant (\(K_a\)) can also be expressed as:
\(K_a = C\alpha^2 = C\left(\frac{\Lambda_m}{\Lambda_m^\circ}\right)^2\)
Rearranging gives us an expression reflective of the equation:
\(\Lambda_m^2 C - K_a \Lambda_m + K_a \Lambda_m^{\circ 2} = 0\)
This equation represents a quadratic relationship between molar conductivity, concentration, and the dissociation constant of a weak electrolyte.
Let's evaluate the given options:
Therefore, the correct answer is option \(\Lambda_m^2 C - K_a \Lambda_m + K_a \Lambda_m^{\circ 2} = 0\).
The relationship between molar conductivity $\Lambda_m$, molar conductivity at infinite dilution $\Lambda_m^\circ$, and concentration $C$ for a weak electrolyte can be derived from the dissociation equilibrium. The correct equation involves the dissociation constant $K_a$ and accounts for the variation of $\Lambda_m$ with concentration. For weak electrolytes, the molar conductivity $\Lambda_m$ is related to the degree of dissociation $\alpha$ as:
\[ \alpha = \frac{\Lambda_m}{\Lambda_m^\circ}. \]
The dissociation constant $K_a$ is expressed as:
\[ K_a = \frac{C\alpha^2}{1 - \alpha}. \]
Substituting $\alpha =\frac{\Lambda_m}{\Lambda_m^\circ}$ into the equation:
\[ K_a = \frac{C \left(\frac{\Lambda_m}{\Lambda_m^\circ}\right)^2}{1 - \frac{\Lambda_m}{\Lambda_m^\circ}}. \]
Simplifying and rearranging, the equation becomes:
\[ \Lambda_m^2 C - K_a \Lambda_m^{\circ 2} + K_a \Lambda_m \Lambda_m^\circ = 0. \]
This is the equation that correctly represents the relationship between molar conductivity, concentration, and dissociation constant for a weak electrolyte.
Final Answer: (1)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,