Question:

Which one of the following lanthanoids does not form \(\mathrm{MO_2}\)? [M is lanthanoid metal]

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MO2 needs the +4 state: Ce, Pr, Nd, Tb and Dy form it; Yb prefers +2 and +3.
Updated On: Nov 4, 2026
  • Nd
  • Dy
  • Yb
  • Pr
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The Correct Option is C

Solution and Explanation

Lanthanoids mostly show the +3 state. The +4 state (needed for \(\mathrm{MO_2}\)) is shown by Ce, Pr, Nd, Tb and Dy, which form oxides like CeO2, PrO2, NdO2, TbO2, DyO2.
Yb (\(4f^{14}6s^2\)) shows +2 (stable \(4f^{14}\)) and +3, not +4.
So Yb does not form \(\mathrm{MO_2}\).
Answer: (3) Yb
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