Question:

Arrange the following metal complex/compounds in the increasing order of spin only magnetic moment. Presume all the three, high spin system.

(Atomic numbers Ce = 58, Gd = 64 and Eu = 63)

(a) \(\mathrm{(NH_4)_2[Ce(NO_3)_6]}\)

(b) \(\mathrm{Gd(NO_3)_3}\) and

(c) \(\mathrm{Eu(NO_3)_3}\)

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Find the oxidation state and f-electron count of each lanthanoid, then use \(\mu=\sqrt{n(n+2)}\).
Updated On: Nov 4, 2026
  • (a) < (b) < (c)
  • (b) < (a) < (c)
  • (a) < (c) < (b)
  • (c) < (a) < (b)
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The Correct Option is C

Solution and Explanation

(a) \(\mathrm{(NH_4)_2[Ce(NO_3)_6]}\): Ce is +4, \(\mathrm{Ce^{4+}} = [Xe]4f^0\), n = 0, \(\mu = 0\).
(b) \(\mathrm{Gd^{3+}}\) (Z = 64): [Xe]4f7, n = 7, \(\mu=\sqrt{7\times 9}=\sqrt{63}\approx 7.94\) BM.
(c) \(\mathrm{Eu^{3+}}\) (Z = 63): [Xe]4f6, treated as high spin with n = 6, \(\mu=\sqrt{6\times 8}=\sqrt{48}\approx 6.93\) BM.
Order of increasing magnetic moment: (a) < (c) < (b).
Answer: (3) (a) < (c) < (b)
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