First, let's solve the inequality:
\[
2 - 5x \leq \frac{-6x - 5}{3}.
\]
Multiply both sides by 3 to eliminate the denominator:
\[
3(2 - 5x) \leq -6x - 5.
\]
Expanding both sides:
\[
6 - 15x \leq -6x - 5.
\]
Now, move the terms involving \( x \) to one side:
\[
6 + 5 \leq -6x + 15x.
\]
Simplifying:
\[
11 \leq 9x.
\]
Now, divide by 9:
\[
x \geq \frac{11}{9}.
\]
Thus, the solution is \( x \geq \frac{11}{9} \), which corresponds to a closed circle on \( \frac{11}{9} \) and extending to the right.
The representation that matches this solution is option (C).